How can I convert this string to list of lists? [duplicate]

This question already has answers here: How to convert string representation of list to a list (19 answers) Closed 6 years ago.

If a user types in [[0,0,0], [0,0,1], [1,1,0]] and press enter, the program should convert this string to several l开发者_高级运维ists; one list holding [0][0][0], other for [0][0][1], and the last list for [1][1][0]

Does python have a good way to handle this?

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>>> import ast
>>> ast.literal_eval('[[0,0,0], [0,0,1], [1,1,0]]')
[[0, 0, 0], [0, 0, 1], [1, 1, 0]]

For tuples

>>> ast.literal_eval('[(0,0,0), (0,0,1), (1,1,0)]')
[(0, 0, 0), (0, 0, 1), (1, 1, 0)]

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>>> import json
>>> json.loads('[[0,0,0], [0,0,1], [1,1,0]]')
[[0, 0, 0], [0, 0, 1], [1, 1, 0]]

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This is a little more flexible than Satoru's, and doesn't use any libraries. Still, it won't work with more deeply nested lists. For that, I think you would need a recursive function (or loop), or eval.

str = "[[0,0,0],[0,0,1],[1,1,0]]"
strs = str.replace('[','').split('],')
lists = [map(int, s.replace(']','').split(',')) for s in strs]

lists now contains the list of lists you want.

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[[int(i) for i in x.strip(" []").split(",")] for x in s.strip('[]').split("],")]

a list comprehension in a list comprehension... but that will melt your brain

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>>> import re    
>>> list_strs = re.findall(r'\[\d+\,\d+\,\d+\]', s)
>>> [[[int(i)] for i in l[1:-1].split(',')] for l in list_str]

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>>> string='[[0,0,0], [0,0,1], [1,1,0]]'
>>> eval(string)
[[0, 0, 0], [0, 0, 1], [1, 1, 0]]
>>> a=eval(string)
>>> a
[[0, 0, 0], [0, 0, 1], [1, 1, 0]]

before passing your string to eval(), do the necessary sanitization first.