Call virtual method from base class on object of derived type

class Base
{
public:
    virtual void foo() const
    {
        std::cout << "Base";
    }
};

class Derived开发者_开发知识库 : public Base
{
public:
    virtual void foo() const
    {
        std::cout << "Derived";
    }
};

Derived d; // call Base::foo on this object

Tried casting and function pointers but I couldn't do it. Is it possible to defeat virtual mechanism (only wondering if it's possible)?

---

To explicitly call the function foo() defined in Base, use:

d.Base::foo();

---

d.Base::foo();

Note that d.foo() would call Derived::foo regardless of whether foo was virtual or not.