I am looking to use javascript to extract the GET para开发者_开发知识库meters from a user inputed url.
For example is a user enters a url say:
http://www.youtube.com/watch?v=ee925OTFBCA
I could get the v parameter
'ee925OTFBCA' as a variable
Thanks in Advance.
This should do the trick
// include this somewhere available 
var Query = (function(){
    var query = {}, pair, search = location.search.substring(1).split("&"), i = search.length;
    while (i--) {
        pair = search[i].split("=");
        query[pair[0]] = decodeURIComponent(pair[1]);
    }
    return query;
})();
var v= Query["v"]
This only runs its computation once and creates an object with name/value pairs corresponding to those supplied as parameters
From here:
function getURLParam(strParamName){
  var strReturn = "";
  var strHref = window.location.href;
  if ( strHref.indexOf("?") > -1 ){
    var strQueryString = strHref.substr(strHref.indexOf("?")).toLowerCase();
    var aQueryString = strQueryString.split("&");
    for ( var iParam = 0; iParam < aQueryString.length; iParam++ ){
      if (
aQueryString[iParam].indexOf(strParamName.toLowerCase() + "=") > -1 ){
        var aParam = aQueryString[iParam].split("=");
        strReturn = aParam[1];
        break;
      }
    }
  }
  return unescape(strReturn);
}
To use it:
 var v = getURLParam('v')
You can use a function like this:
function querystring(key) {
   var re=new RegExp('(?:\\?|&)'+key+'=(.*?)(?=&|$)','gi');
   var r=[], m;
   while ((m=re.exec(document.location.search)) != null) r.push(m[1]);
   return r;
}
Example:
var v = querystring('v')[0];
The function returns an array with all the values found in the query string. If you have a query string like ?x=0&v=1&v=2&v=3 the call querystring('v') returns an array with three items.
This is my simple snippet:
function extractParamValue(url, name) {
    var pos = url.indexOf(name+'=')+name.length+1;
    var value = url.substring(pos, url.indexOf('&', pos));
    return value;
}
 
         
                                         
                                         
                                         
                                        ![Interactive visualization of a graph in python [closed]](https://www.devze.com/res/2023/04-10/09/92d32fe8c0d22fb96bd6f6e8b7d1f457.gif) 
                                         
                                         
                                         
                                         加载中,请稍侯......
 加载中,请稍侯......
      
精彩评论