Say a string is abc/xyz/IMPORTANT/DATA/@#!%@!%, and I just want IMPORTA开发者_开发技巧NT/DATA/!%#@%!#%
I am terrible at regex, and really haven't learned JavaScript API yet
Use indexOf and substring. You don't need regex for this.
You can use the start parameter to indexOf to search from a given position. If you search after the first /, you can find the index of the second /.
s = "abc/def/ghi/jkl";
s = s.substring(s.indexOf('/', s.indexOf('/') + 1) + 1);
document.writeln(s); // "ghi/jkl"
Note that this assumes that there will always be at least two /. If there isn't, this will keep s as it is.
s = "abc/xyz";
s = s.substring(s.indexOf('/', s.indexOf('/') + 1) + 1);
document.writeln(s); // "abc/xyz"
If you want to use regex anyway, it's something like this:
s = "abc/def/ghi/jkl";
s = s.replace(/[a-z]+\/[a-z]+\//, '');
document.writeln(s); // "ghi/jkl"
Again, this assumes that there will always be at least two /.
If the text is always like your current example you might be able to simply use substring and indexOf to cut it starting from the second occurence of the "/".
Otherwise /([^\/]+\/[^\/]+\/)/, or Blair's answer might be a good regexp to use.
Or /^([^\/]+\/[^\/]+\/)/ if it has to start at the beginning of the string.
I think
yourstring.replace(/[a-z]+\/[a-z]+\/(.+)/g, "$1");
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