how to replace only the first value of MODE parameter in the bash script from "ON" to "OFF" by VB script?
the bash script location: C:\folder_scripts\script.bash
THX
Yael
the bas开发者_如何学Goh script (txt file):
#!/bin/bash
MODE=ON
if [[ $MODE = ON ]]
then
echo "the machine is on line"
elif [[ $MODE = OFF ]]
echo "the machine is OFF line"
fi
Replace has a Count and Start argument, setting Count to 1 will replace the first occurance:
Set fs = CreateObject("Scripting.FileSystemObject")
sf = "C:\folder_scripts\script.bash"
Set f = fs.OpenTextFile(sf, 1) ''1=for reading
s = f.ReadAll
s = Replace(s, "MODE=On", "MODE=Off",1,1)
f.Close
Set f = fs.OpenTextFile(sf, 2) ''2=ForWriting
f.Write s
f.Close
If the text could vary, for example, in the number of spaces between MODE and equals sign, you can read the text line by line (s=f.ReadLine) until you find the first line in which MODE occurs.
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