Returning different results or throwing exceptions from successive calls to Moq Mock

I get a Moq object to return different values on successive calls to a method. This is done by this extension method:

public static void ReturnsInOrder<T, TResult>(this ISetup<T, TResult> setup, params TResult[] results) where T : class
{
    setup.Returns(new Queue<TResult>(results).Dequeue);
}

Now I want one of the calls to throw an exception while others return something. Has anyone done this before?

If i do this

mock.Setup(m => m.SomeMethod())
 开发者_运维百科   .Throws(new Exception());
mock.Setup(m => m.SomeMethod())
    .Returns("ok");

then the the first setup is overwritten and only the second setup persists.

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Nowadays Moq (version 4+) supports this through its SetupSequence method. See this post for an introduction.

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I used callback chaining while developing retry proxy.

var src = new Mock<ITest>();
src.Setup(s => s.RaiseError()).Callback(() => 
src.Setup( s => s.RaiseError())).Throws<Exception>();

const int retryCount = 1;
var proxy = RetryProxy.MakeFor(src.Object, retryCount);

proxy.RaiseError();
src.Verify(s => s.RaiseError(), Times.Exactly(retryCount+1));

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Phil Haack blogged about this.

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Use SetupSequence(...) on the mock object.

For example the following will throw the exception on the first call and return someResponse on the second call:

myService.SetupSequence(s => s.PlaceOrder())
    .Throws(new Exception())
    .Returns(someResponse);