I have a data table and I want to delete a row here is my code it's throwing me an exception
foreach (DataRow row in dt1.Rows)
{
    if ((row["Name"] == "Select a Lookbook") || (row["Name"] == "Create a new Lookbook"))
    {
        row.Delete();
        dt1.AcceptChanges();
    }
}
I even tried outside the if statment and outside forloop still throws me error any idea how t开发者_C百科o achieve this task this is the exception I get:
Collection was modified; enumeration operation might not execute.
Final working Code:
foreach (DataRow row in dt1.Select())
{
    if ((row["Name"] == "Select a Lookbook") ||    (row["Name"] == "Create a new Lookbook"))
    {
        row.Delete();                                       
    }
}
Instead of using dt1.Rows, use dt1.Select()
The goal here is not to use the collection itself, but rather an array of row that is not the Rows collection
Create a list of rows to delete while iterating over DataTable.Rows, then delete them all separately.
Non-LINQ solution:
List<DataRow> rowsToDelete = new List<DataRow>();
foreach (DataRow row in dt1.Rows)
{
    if ((row["Name"] == "Select a Lookbook") || 
        (row["Name"] == "Create a new Lookbook"))
    {
        rowsToDelete.Add(row);
    }
}
foreach (DataRow row in rowsToDelete)
{
    row.Delete();
}
dt1.AcceptChanges();
LINQ solution:
List<DataRow> rowsToDelete = dt1.Rows.AsEnumerable()
    .Where(row => (row["Name"] == "Select a Lookbook") || 
                  (row["Name"] == "Create a new Lookbook"))
    .Tolist();
foreach (DataRow row in rowsToDelete)
{
    row.Delete();
}
dt1.AcceptChanges();
This is how I did it when I ran into this issue.
            Dim index As Integer = 0
            Dim count As Integer = resultsDT.Rows.Count - 1
            For i As Integer = 0 To count
                If resultsDT.Rows(index).Item("something") = "something" Then
                    resultsDT.Rows(index).Delete()
                    resultsDT.AcceptChanges()
                    index = index - 1
                End If
                index = index + 1
                i = i + 1
            Next
 
         
                                         
                                         
                                         
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