Can someone explain why 开发者_高级运维this algorithm is free from deadlock specifically? thanks
Because the need for release messages is removed (assuming all participants are correctly clock-synchronized and you also use timeouts to detect crashed participants). Thank God for Wikipedia.
![Interactive visualization of a graph in python [closed]](https://www.devze.com/res/2023/04-10/09/92d32fe8c0d22fb96bd6f6e8b7d1f457.gif)
加载中,请稍侯......
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