how can I get the ip address of the request in a regested function of python xmlrpc server

I'm writing a simple xmlrpc programe in python. something like the following:

def foo(data):

    # I want get the calling client's IP address here... How can I ?

serv开发者_C百科er=SimpleXMLRPCServer.SimpleXMLRPCServer((host, port))
server.register_function(foo)

server.handle_request()

As can be seen in the above, I want to get the client IP address in the registed function "foo", how can I ?

---

You may do so by subclassing the server (and possibly the handler, too). E.g.:

class MyXMLRPCServer(SimpleXMLRPCServer.SimpleXMLRPCServer):
    def process_request(self, request, client_address):
        self.client_address = client_address
        return SimpleXMLRPCServer.SimpleXMLRPCServer.process_request(
            self, request, client_address)

server=SimpleXMLRPCServer.MyXMLRPCServer((host, port))

Now server.client_address gives you the desired data. Note that this direct, short coding only works for the single-threaded case (which you're using anyway by choosing the simple server in your code) -- the need to work with the handler comes in if you want to go multi-threaded.