How to wrap return type of ajax call in success with function

开发者_如何学PythonI have a Web Service and it always brings back one object from my class that i defined on the server side.

in success method of $.ajax function i always get the this object. And on the client side i want to add couple of functions to display its properties quickier.

Is there a way do that ? (JSON object will return, i am worrying about that)

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You can extend javascript objects and add methods to it:

var json = { name: 'john' };
json.print = function() {
    alert('my name is ' + this.name);
};
json.print();

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As you already told me in your last question about this topic

how can i add a function to json object which has __type attribute?

you want to have a global functionally. Since you still can't add a function into json you should declare a global function like:

var props = (function(){
   var spacing = '';

   function props(json, deep) {
      if(typeof json === 'object'){
         for(var prop in json){
             if(typeof json[prop] === 'object'){             
                spacing += '   ';
                props(json[prop], true); 
             }
             else{                
               console.log(spacing, prop, ': ', json[prop]);
             }
         }
      }
   }

   return props;
}());