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Simple syntax for getting a member of a type in extension method (C#)

开发者 https://www.devze.com 2023-01-09 04:44 出处:网络
I\'m trying to 开发者_运维知识库write an extension method that will give me the MemberInfo representing a member of a given type, using lambda expressions. Ideally, I\'d like to be able to write

I'm trying to 开发者_运维知识库write an extension method that will give me the MemberInfo representing a member of a given type, using lambda expressions. Ideally, I'd like to be able to write

var info = MyType.GetMember(m => m.MyProperty);

or, also acceptable

var info = typeof(MyType).GetMember(m => m.MyProperty);

or even

var info = typeof(MyType).GetMember((MyType m) => m.MyProperty);

I have a generic method signature that works, but requires me to specify all the type parameters, and I'd very much like C# to infer them. As far as I can see, if I just find the right way to specify the extension method signature, there should be enough information in (at least the last one of) the code snippets to infer everything - but according to the compiler, there isn't.

I've read an old blog post on static extension methods but I haven't been able to find anything on it more recent than that. If that came true, I'd be able to write

public static MemberInfo GetMember<TType, TReturnType>(static TType, Expression<Func<TType, TReturnType>> member)

which would solve my problem. But as I said, I seem to be stuck with instance extensions, in which case

public static MemberInfo GetMember<TType, TReturnType>(this Type t, Expression<Func<TType, TReturnType>> member)

just isn't good enough for the compiler to infer type members.


How about this:

public static MemberInfo GetMember<TType, TReturnType>
    (this TType ignored,
     Expression<Func<TType, TReturnType>> expression)

which you'd then call like this:

default(MyType).GetMember(m => m.MyProperty)

It's a bit icky, but using default(MyType) is a simple and efficient way of getting an expression of type MyType, which is what you want for type inference.


If you don't have an instance, I think the best you can do is:

public static MemberInfo GetMember<TType, TReturnType>(Expression<Func<TType, ReturnType>> member)

Then use like this:

MemberInfo info = YourClass.GetMember((YourConcreteType instance) => instance.Property);

You can keep an overload that takes an instance as the first argument, so you can use extension method syntax whenever you have an instance:

public static MemberInfo GetMember<TType, TReturnType>(this TType instance, Expression<Func<TType, ReturnType>> member)

Then use like this:

MemberInfo info = yourInstanceOfTType.GetMember(instance => instance.Property);
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