I have url like this
/cp/foo-bar/another-testing
how to parse it with the patt开发者_如何转开发ern
/cp/{0}-{1}/{2}
results will be
0:foo
1:bar
2:another-testing
I need a global solution to parse all kind of url with a pattern like that. I mean using {0}, {1} flag.
if (preg_match('#/cp/([^/]+?)-([^/]+?)/([^/]+)#'), $url, $matches)) {
//look into $matches[1], $matches[2] and $matches[3]
}
Instead of using {0}, {1}, {2}, I offer a new way: using {$s[0]}, {$s[1]}, {$s[2]}:
$your_url = '/cp/foo-bar/another-testing';
$s = explode('/', $your_url);
if(!$s[0])
array_shift($s);
if($temp = array_pop($s))
$s[] = $temp;
//then
$result = "/cp/{$s[0]}-{$s[1]}/{$s[2]}";
加载中,请稍侯......
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