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PHP convert date from a MySQL query

开发者 https://www.devze.com 2023-01-12 04:09 出处:网络
I think this is a simple question.开发者_高级运维We have a MySQL database with a DATE field, the date is stored in US format (2010-06-01).

I think this is a simple question.开发者_高级运维 We have a MySQL database with a DATE field, the date is stored in US format (2010-06-01).

In my PHP page where I'll display the date, I simply want to convert this date into a UK format (01-06-2010).

Any help and advice appreciated!

Thanks,

Homer.


You didn't specify and your example is ambiguous, but I'll assume you're talking about outputting in day-month-year format. You can use strtotime to parse a string date into a unix timestamp, and then give that timestamp to date along with the format that you'd like to output your date in:

date("d-m-Y", strtotime($date_from_mysql));

The manual page for date lists all the formatting options that you can give. In this case, d represents the day as a zero-padded number, m represents the month as a zero-padded number, and Y represents the year as a four digit number. Any characters that don't have a specific meaning for date come across as-is.


You can do it right from mysql using DATE_FORMAT() function. example : "SELECT DATE_FORMAT(date_column,'%d-%m-%Y') as my_formated_date;" will do what you need , just make sure to use in fetch method my_formated_date column


You can parse the date with this function:

http://php.net/manual/en/function.strtotime.php

It will return an integer which is number of seconds since 1970 (called a Unix timestamp).

Then use this function to format that number any way you like:

http://ca3.php.net/manual/en/function.date.php


You can also create a Date object in PHP using the DateTime::createFromFormat feature.

<?php
    $date = DateTime::createFromFormat('Y-m-d', $sql_date);
    echo $date->format('d-m-Y');
?>
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