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Get typedef of current class

开发者 https://www.devze.com 2023-01-16 06:48 出处:网络
I\'m currently using boost::intrusive_ptr together with my GUI classes. Although this is more or less a convenience question, is there a proper way to get the typename of the current class?

I'm currently using boost::intrusive_ptr together with my GUI classes. Although this is more or less a convenience question, is there a proper way to get the typename of the current class? The reason I'm asking is that I have a macro for typedef'ing the different pointer types:

#define INTRUSIVE_PTR_TYPEDEFS(CLASSNAME) typedef boost::intrusive_ptr<CLASSNAME> Ptr; \
typedef boost::intrusive_ptr<const CLASSNAME> CPtr; \
typedef CLASSNAME* WeakPtr; \
typedef const CLASSNAME* CWeakPtr;

...

class Widget
{
public:
    INTRUSIVE_PTR_TY开发者_开发百科PEDEFS(Widget);
    ...
};

class Button : public Widget
{
public:
    INTRUSIVE_PTR_TYPEDEFS(Button);
    ...
};

It would be much more comfortable to have CLASSNAME automatically deduced so you could simply copy'n'paste it into the class body. I'm using the compiler shipped with Visual Studio 2010.

Thanks in advance!


No, that's not possible to do in C++.


Hmm, one idea I have is to call constructor and typename on this pointer... Another way could be to create a template metaprogram for creating classes, which will do the typedefs as well.

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