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VCBuild task in MSBuild - change outputpath

开发者 https://www.devze.com 2023-01-26 03:51 出处:网络
I\'m attempting to write an automated build for one of our products, and I\'ve hit up against a wall for some of our VC++ projects: I need to be able to set the output path to where the assemblies wil

I'm attempting to write an automated build for one of our products, and I've hit up against a wall for some of our VC++ projects: I need to be able to set the output path to where the assemblies will be copied once its done.

Here is a makeshift msbuild file:

<Project DefaultTargets="Build"
         xmlns="http://schemas.microsoft.com/developer/msbuild/2003"
         ToolsVersion="3.5">
 <Target Name="Build">
   <VCBuild Projects="C:\src\SomeProject\SomeProject.vcproj"
            ToolPath="C:\Program Files\Microsoft Visual Studio 9.0\VC\vcpackages"
          开发者_开发百科  Configuration="Debug" />
 </Target>
</Project>

Stijn's Answer:

I thought I'd use this space to clarify how I personally used Stijn's answer to solve this. He has some code in his MSBuild file that writes the vsprops file for him. I decided to take a simpler approach and just write the file manually.

I created this file, called build.vsprops (my output path is V:)

<?xml version="1.0"?>
<VisualStudioPropertySheet ProjectType="Visual C++"
                           Version="8.00"
                           Name="Overrides"
                           OutputDirectory="V:\">
  <Tool Name="VCCLCompilerTool"
        AdditionalUsingDirectories="V:\" />
</VisualStudioPropertySheet>

Then I edited my MSBuild file to add the Override parameter:

<Project DefaultTargets="Build"
         xmlns="http://schemas.microsoft.com/developer/msbuild/2003"
         ToolsVersion="3.5">
 <Target Name="Build">
   <VCBuild Projects="C:\src\SomeProject\SomeProject.vcproj"
            ToolPath="C:\Program Files\Microsoft Visual Studio 9.0\VC\vcpackages"
            Configuration="Debug"
            Override="$(MSBuildProjectDirectory)\build.vsprops" />
 </Target>
</Project>


have a look at the Override parameter for the VCBuild task. Basically you specify a property sheet which you can use to override whatever property you want (it has the same effect as adding a property sheet to the top of the list in a project within VS). You could even generate the override file using the WriteLinesToFile task.

Example:

<PropertyGroup>
  <VCOverridesFile Condition=" '$(VCOverridesFile)'=='' ">overrides.vsprops</VCOverridesFile>
  <VCOverridesOpen>%3C?xml version=%221.0%22?%3E%0D%0A%3CVisualStudioPropertySheet ProjectType=%22Visual C++%22 Version=%228.00%22 Name=%22My Overrides%22%3E</VCOverridesOpen>
  <VCOverridesClose>%3C/VisualStudioPropertySheet%3E</VCOverridesClose>
  <MyOutPath>&lt;Tool Name="VCLinkerTool" OutputFile ="c:\my.exe"/&gt;</MyOutPath>
</PropertyGroup>

<Target Name="WriteOverridesFile">
  <WriteLinesToFile
    File="$(VCOverridesFile)"
    Lines="$(VCOverridesOpen);$(AdditionalVCOverrides);$(VCOverridesClose)"
    Overwrite="true" />
</Target>

Then pass $(VCOverridesFile) to the Override property and make sure your VCBuild Task DependsOnTarget WriteOverridesFile.


Doing it the dirty way you can pass output directory path through command line arguments of msbuild.

msbuild yourProject /p:OutDir=yourPath

Although I suspect, there should be the better way to accomplish the task. The main idea is to set 'OutDir' property in such a way that it will not be overriden by your SomeProject.vcproj


if you are using Azure DevOps and needs to create a YAML do build a .net framework (vintage[old])

- task: VSBuild@1
  inputs:
    solution: '**\*.sln'
    msbuildArgs: '/p:DeployOnBuild=true /p:SkipInvalidConfigurations=false /p:OutDir="$(System.DefaultWorkingDirectory)\publish_output"'
    platform: 'Any CPU'
    configuration: 'Release'
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