Suppose I have a Makefile:
all: $(BINARY)
$(BINARY): $(OBJS) $(DEBUG_OBJS)
#Link objects here
$(OBJS): headers
#Compile code into objects without debug option
$(DEBUG_OBJS): headers
#Compile code into objects with debug option
开发者_Go百科headers:
#Create on-the-fly header files
As you can see, the target headers is required by both $(OBJS) and $(DEBUG_OBJS). The question is, will headers be called twice? Also, would the below code be equal/equivalent to the above:
all: $(BINARY)
$(BINARY): headers $(OBJS) $(DEBUG_OBJS)
#Link objects here
$(OBJS):
#Compile code into objects without debug option
$(DEBUG_OBJS):
#Compile code into objects with debug option
headers:
#Create on-the-fly header files
in that, would headers get called before $(OBJS) and $(DEBUG_OBJS) by $(BINARY)?
No, headers will be done just once.
You can write a simple makefile to test it:
all: foo bar
foo: baz
bar: baz
baz:
echo 'hi'
On doing make, hi will be echoed just once.
And in your 2nd case make sees that $(BINARY) depends on headers first, so it goes and does headers before other dependencies.
加载中,请稍侯......
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