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PyAudio.open, how to use?

开发者 https://www.devze.com 2022-12-12 09:38 出处:网络
I\'m trying to make a pyaudio input stream开发者_如何转开发 but can\'t figure out how to make it.

I'm trying to make a pyaudio input stream开发者_如何转开发 but can't figure out how to make it. What I did is:

a = pyaudio.PyAudio()

Then tried to call a.open() but I don't know the arguments I should type in. It asks me to check Stream.init for a reference, but I don't know what a PA_MANAGER is and the documentation isn't useful at all about it.


Perhaps you could start by modfying some of the examples?

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