If I have a generic constraint where C must be a struct:
class MyNum<C> where C : struct
{
    C a;
    public MyNum(C a)
    {
        this.a = a;
    }
}
struct myStruct
{
    public int a;
}
I understand that this compiles:
    myStruct n = new myStruct();
    n.a = 5;
    MyNum<myStruct> str = new MyNum<myStruct>(n);
But why would this compile. ¿Is number 5 a structure?
I thought by doing this:
int b = 5;
b would be of type int, but not type struct. I guess I´m missin开发者_StackOverflowg something here.
Also just to use the correct terminology:
int b = 5; 
Am I instantiating b? Creating an int instance? For some reason in my mind when I think of "instances" I think of reference types.
Here:
Car c1 = new Car(); 
Here I understand that I´m creating a Car instance or instantiating c1.
int is a struct.
Look at Int32 definition on MSDN
EDIT:
Doing:
 int i = 5;
as well as:
MyStruct m = new MyStruct();
you're creating a memory location as big as the necessary space to contain the struct.
The difference with reference types, is that variables m and i aren't references to those memory locations storing values, but they're basically "the value itself".
Infact when you do:
MyStruct m1 = new MyStruct();
MyStruct m2 = m1;
m2 doesn't represent the same memory location of m1, but the content of m1 is copied in a new location of memory represented by the variable m2
According to MSDN with a struct Type constraint, The type argument must be a value type. Any value type except Nullable can be specified.
And as diggEmAll mentioned already int is struct
Yes 5 is an int and int is a structure
 
         
                                         
                                         
                                         
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