seq

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Convert Seq to ArrayBuffer

Is there an开发者_StackOverflow中文版y concise way to convert a Seq into ArrayBuffer in Scala?scala> val seq = 1::2::3::Nil[详细]

2023-04-07 20:24 分类：问答
F# lists with sequence operators

After having a look at these two threads: Does F# have an equivalent to Haskell's take? , Take N elements from sequence with N different indexes in F#[详细]

2023-04-05 03:37 分类：问答
Scala - Why can't infer List of Seq for a list containing Vector and List?

Trying the following in 2.8.1/2.9.0.1 REPL, the first gives an error. val l = List(Vector(1,2), List(3,4,5))[详细]

2023-04-04 13:13 分类：问答
Seq.Map string->string

all! What is wrong with this code? I cannot understand what I am doing wrong with Seq.Map. Here is the error message: The type \'unit\' is not compatible with the type \'seq<\'a>\'[详细]

2023-03-27 23:45 分类：问答
Monads: What's the difference between seq and >>=?

What\'s the differ开发者_开发百科ence? Does seq guarantee more flow conditions?They aren\'t related at all.[详细]

2023-03-23 16:24 分类：问答
Split seq in F#

I should split seq<a> into seq<seq<a>> by an attribute of the elements. If this attribute equals by a given value it must be \'splitted\' at that point. How can I do that in FSharp?[详细]

2023-03-21 16:51 分类：问答
How can I attach seq to another one by an attribute?

I have a seq of seqs in FSharp. I want to join a seq to the previous one if a predicate returns to true for it.[详细]

2023-03-21 15:21 分类：问答
Expand an seq into individual scalars

I wan开发者_JAVA技巧t to feed the members of a lazy seq produced by map as individual arguments to another function. Is there a function that splices a (lazy) seq? Use apply.[详细]

2023-03-16 12:23 分类：问答
Create sequence of repeated values, in sequence?

I need a sequence of repeated numbers, i.e. 1 1 ... 1 2 2 ... 2 3 3 ... 3 etc. The way I implemented this was:[详细]

2023-03-14 07:38 分类：问答
Initializing an infinite list of BigIntegers

Ok, So I need a list of all the positive integers. What first comes to mind is: let numbers:Seq<bigint>=Seq.initInfinite n...[详细]

2023-03-11 06:00 分类：问答